A person travels along a straight road for the half of the distance with velocity v1 and the remaining half distance with velocity v2 . the average velocity is given by
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Answered by
5
Hey there,
This is a basic formulas which might help you=
n/average velovity=1/v₁+1/v₂+1/v₃+.........1/v₀
where n=number of equal distances in which we have velocities v₁,v₂,etc
In this case, where journey is travelled in 2 equal distance=
1/average velocity=1/v₁+1/v₂
PLEASE MARK AS BRAINLIEST IF HELPFUL!!!
This is a basic formulas which might help you=
n/average velovity=1/v₁+1/v₂+1/v₃+.........1/v₀
where n=number of equal distances in which we have velocities v₁,v₂,etc
In this case, where journey is travelled in 2 equal distance=
1/average velocity=1/v₁+1/v₂
PLEASE MARK AS BRAINLIEST IF HELPFUL!!!
07161020:
plz mark as brainliest
Answered by
10
If x is the total displacement then,
Average velocity = Displacement / Time
= x / (t₁ + t₂)
= x / (x/(2v₁) + x/(2v₂)) ………[∵ Time = Displacement / Velocity]
= 2v₁v₂ / (v₁ + v₂)
∴ Average Velocity of person is 2v₁v₂ / (v₁ + v₂)
Average velocity = Displacement / Time
= x / (t₁ + t₂)
= x / (x/(2v₁) + x/(2v₂)) ………[∵ Time = Displacement / Velocity]
= 2v₁v₂ / (v₁ + v₂)
∴ Average Velocity of person is 2v₁v₂ / (v₁ + v₂)
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