A person travels along the straight road for first half with velocity v1 and second half with velocity v2 find the mean velocity
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let the half lengths be x each thus time taken for first length, t1 = x/20time taken for second length, t2 = x/30thus average velocity = 2x/(t1+t2) = 24 m/s
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29
let the half lengths be x each, displacement = S.
Given, he travels first half is x/2 with v1. Displacement = v1 * x/2
Given, he travels second half is x/2 with v2. Displacement = v2 * x/2.
So, S = v1 * x/2 + v2 * x/2 = (x/2)(v1+v2)
Average velocity = S/x
= (x/2)(v1+v2)/x
= (v1+v2)/2.
Hope this helps!
Given, he travels first half is x/2 with v1. Displacement = v1 * x/2
Given, he travels second half is x/2 with v2. Displacement = v2 * x/2.
So, S = v1 * x/2 + v2 * x/2 = (x/2)(v1+v2)
Average velocity = S/x
= (x/2)(v1+v2)/x
= (v1+v2)/2.
Hope this helps!
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