Question

A person travels by a car at a speed of 180 km h−1. It takes exactly 10 hours by his wristwatch to go from the station A to the station B. (a) What is the rest distance between the two stations? (b) How much time is taken in the road frame by the car to go from the station A to the station B?

Answer 1

Answer:

for the last time this is not chemistry

Answer 2

Explanation:

It is given:

Car’s speed is denoted as v, which is 180 km/hr = 50 m/s

Time, t = 10 hours

Let us consider that the distance at rest be L0.

Apparent distance is shown as

$L^{\prime}=L 01-v 2 / c 2$

Apparent distance, $L^{\prime}=1800 \mathrm{km}=18 \times 10^{5} \mathrm{m}$

Now,

$18 \times 105=\angle 01-5023 \times 1082$

$\mathrm{LO}=25 \times 10-9 \mathrm{m}+18 \times 105$

So, the distance at rest is 25 nm, which is more than 1800 km.

(b) In the road, the time taken by the car to cover a distance be denoted as t. Then,

$\mathrm{t}=5 \times 10-8+0.36 \times 105=10 \text { hours }+0.5 \mathrm{ns}$