Question

Suppose Swarglok (heaven) is in constant motion at a speed of 0.9999c with respect to the earth. According to the earth's frame, how much time passes on the earth before one day passes on Swarglok?

Answer 1

Answer:

0.8888c is the answer.............

Answer 2

Explanation:

It is given in the question that:

Swarglok has the speed, v = 0.9999c

Proper time interval = On Swarglok, one day

Suppose t‘ is the number of days passing on Earth before one day passes on Swarglok.

Now,$\Delta t^{\prime}=\Delta t 1-v 2 c 2=10.014141782=11-0.99992 c 2 c 2=70.712 \text { days. }$

Thus, before one day passes on Swarglok, the time passing on the earth is 70.7 days.