A person travels from a to b at 60km/hr and returns from b to a at 90 km/hr.find the average speed of the journey
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distance from a to b=dist. from b to a=d
time from a to b=dist./speed=d/60
time from b to a= ". =d/90
avg.speed=total distance/total time
=d+d/d/60+d/90
=2d/3d+2d/180
=2d/5d/180
=2d*180/5d
=72km /h
time from a to b=dist./speed=d/60
time from b to a= ". =d/90
avg.speed=total distance/total time
=d+d/d/60+d/90
=2d/3d+2d/180
=2d/5d/180
=2d*180/5d
=72km /h
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