Question

A person uses a mature having 6 parts pure wine and parts of water. After
ng out some portion of the mixture, he adds equal amount of pure water to
the remaining portion of the mature such that the amount of wine and water will
be in the ratio 1:1. What part of mature is taken out?​

Answer 1

Answer:

answer for this question is 1/12

Answer 2

Answer: 2/7th part of the mixture is taken out.

Step-by-step explanation:

Let's assume that the person starts with a total of x parts of mixture, of which 6 parts are wine and (x - 6) parts are water.

After taking out some portion of the mixture, the amount of remaining mixture is (x - y) parts, where y is the part of the mixture taken out.

Now, the person adds an equal amount of pure water to the remaining mixture, which means he adds (y/2) parts of pure water. After this addition, the amount of water in the mixture becomes (x - 6 - y/2) parts.

Since the ratio of wine to water is 1:1 in the final mixture, we can write:

6 / (x - y) = (x - 6 - y/2) / (x - y/2)

Simplifying this equation, we get:

12x - 84y = x^2 - 13xy + 3y^2

Since we need to find the part of the mixture taken out, which is y/x, we need to solve this equation for y/x.

Solving the equation, we get:

y/x = 2/7

Therefore, 2/7th part of the mixture is taken out.

View more such questions :

https://brainly.in/question/14452485

#SPJ2