Question

A person walking 5/6 of his usual rate is 40 minutes late. What is his usual time? Ans. 3 hours 20 minutes.

Answer 1

Explanation:

Lets assume that usual rate is V m/s.

And He covers distance D metre in t minute.

So, Vt =D ...i

According to question he travels 5/6 of his usual rate. And covers the distance D in t+40 minutes.

So, V5/6 (t + 40) = D ...ii

Dividing i by ii we get

6t/5(t+40) = 1

6t = 5t + 200

t = 200 min

200 min = 3 hr 20 min