A person walking at 4 Kmph reaches his office 8 minutes late. If he walks at 6 Kmph, he reaches there 8
minutes earlier. How far is the office from his house?
Answers
Answer:
let the distance be x km
time taken with 4kmph=x/4hr=x*60/4 min
Allow time=15x-8 mins
similarly x/6 hr=60x/6=10x mins
so 15x-8=10x+8
5x=16
x=16/5 =3.2 km ans
Step-by-step explanation:
so Distance (D) = Speed (s) * Time (T)
the Distance to office - wont change - it will always be constant. And the amount of time he needs to be exactly on time is also a constant (T)
and we know if he walks 4KPH he gets there 8 minutes late - lets call that (T+8)
so 4* (T+8)= D or 4T+32=D
and we know if she walks 6KPH (women are always faster than men) she arrives 8 minutes early - lets call that (T-8) - can you see this coming?
so 6*(T-8) =D or 6T-48= D hmm- interesting, they both +D
sooo 4T+32=6T-48 if we subtract 4T from both sides of the equation we get
32=2T-48 now add 48 to both sides and we get 80=2T or T= 40 minutes
when he walked 4 KPH he was 8 minutes late- so 40+8 +48 or o.8 hours (you remembered to convert to hours, right?)
do get D we multiply Speed times time 4KPH*0.8 hours = 3.2 KM
checking the second equation - when she was 8 minutes early 40–8= 32 or .533 hours 6*.533= 3.2 km :)
please add me in brainleast
Answer:
Let the distance covered by a person be 'x'
we know that time=distance/speed
8 min late+8 min early=x/4*60 min - x/6*60 min
16= 15x - 10x
16= 5x
x=16/5
x= 3.2 km
Step-by-step explanation: