Physics, asked by kamranalam42, 10 months ago

a person walks 80 m east then turns right through angle 143 degrees walks further 50m and stops his position relative to the starting point is

Answers

Answered by amitnrw
16

50 m   ,   37° South to East    

Explanation:

       North

West           East

 

       South

     

S  _________80 m __________________

                                                     37°           /    143°

                                                                 /                        

                                                           50  m

                                                            /

                                                       E

East = 80 m

180 - 143 = 37

South = 50Sin37 = 50 * 0.6 = 30 m   => 30 m South

West = 50 Cos37 = 50 * 0.8 = 40 m   => -40 m East

East = 80 - 40 = 40m

South = 30 m

Distance =  √40² + 30²  =  50 m

Angle = Tan⁻¹ (30/40) = 37°

=>  50 m   ,   37° South to East  

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Answered by krrew
10

Answer:

 50 m   ,   37° South to East  

Explanation:

      North

West           East

 

      South

    

S  _________80 m __________________

                                                    37°           /    143°

                                                                /                        

                                                          50  m

                                                           /

                                                      E

East = 80 m

180 - 143 = 37

South = 50Sin37 = 50 * 0.6 = 30 m   => 30 m South

West = 50 Cos37 = 50 * 0.8 = 40 m   => -40 m East

East = 80 - 40 = 40m

South = 30 m

Distance =  √40² + 30²  =  50 m

Angle = Tan⁻¹ (30/40) = 37°

=>  50 m   ,   37° South to East  

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