A person walks along the sides of a square field. Each side is 100m long. What is the maximum magnitude of displacement of the person in any time in terval
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displacement is the shortest side
side of square = 100m
by applying Pythagoras theorem
ac^2=√(100*100) + (100*100)
100√² is the dipslacement
side of square = 100m
by applying Pythagoras theorem
ac^2=√(100*100) + (100*100)
100√² is the dipslacement
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