Question

a person Walks up a stalled accelerator escalator in 90 seconds. when standing the same escalator ,now moving he is carried in 60 Seconds. how much time would it take him to walk after moving escalator?

Answer 1

v1 = walking speed of person v2 = escalator speed The person walks up the stationary escalator (length L) in 90s. L = speed x time = 90v1 The escalotr moves a distance L in 60s. v2 = distance/time = L/60 = (90v1)/60 = 1.5v1 When walking up the escalator, the person`s speed = v1 + v2. time taken = distance/speed t = L / (v1 + v2) t = 90v1/(v1 + v2) Substituting for v2: t = 90v1/(v1 + 1.5v1) = 90 / (1 + 1.5) = 90 / 2.5 =36 s

I hope this is right answer....! :-)