Question

A person wants to get a piece of work done. There are 2 workers 'A' and 'B'. 'A' said I will take 8 days less than the time taken by 'B' to finish the piece of work. If both 'A' and 'B' together do the same piece of work, they can finish it in 3 days. Find the time taken by 'B' alone to finish the work.

Answer 1

let B alone finish the work in X days
therefore A alone can finish the work in X-8 days
A's one day work = 1/ X-8 and B's one day work = 1/X
given : A+B can finish the work in 4 days
therefore (A+B)'s one day work = 1/3
A's one day work + B's one day work = 1/3
ATQ :
1/X-8 + 1/X =1/3
(X) square -14X + 24
X = 2, 12