a person was climbing on a building. he sleeps 1m for every 5m he climbs up. If d building is 53m high and he takes 5sec to climb every 1 metre, find the total time taken by him to get to the top of the building.
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Answered by
324
THE PERSON CLIMBS 5m AND SLIPS 1m
TO CLIMB Im HE TAKES 5 SECONDS
SO FOR 5m HE TAKES 5x5= 25 SECONDS
AS HE SLIPS 1m FOR EVERY 5m CLIMB
IN EACH ATTEMPT HE CLIMBS 5-1=4 m in 25 SECONDS
TOTAL HEIGHT OF THE BUILDING= 53m
SO HE WILL NEED 53/4= 13 (remainder 1 ignored as he will not slip after the last climb)
SO, TIME TAKEN TO CLIMB THE BUILDING = 25x13=325 SECONDS
ANS:: 325 SECONDS
TO CLIMB Im HE TAKES 5 SECONDS
SO FOR 5m HE TAKES 5x5= 25 SECONDS
AS HE SLIPS 1m FOR EVERY 5m CLIMB
IN EACH ATTEMPT HE CLIMBS 5-1=4 m in 25 SECONDS
TOTAL HEIGHT OF THE BUILDING= 53m
SO HE WILL NEED 53/4= 13 (remainder 1 ignored as he will not slip after the last climb)
SO, TIME TAKEN TO CLIMB THE BUILDING = 25x13=325 SECONDS
ANS:: 325 SECONDS
sangeetaravisha:
thank you
wlcm
bt y u r ignoring 1 as we can count 5sec of it also for climbing
he wont slip after last climb so we are ignoring it
so cant we add 5 sec of it as he is taking 5sec for 1m
no
y can u clr it... bcoz if we ll not add jt how he ll reach at d top
???
Answered by
23
The time taken by the person to climb the building is 325 seconds.
Given,
Height of the building = 53 m
Time taken to climb every 1 meter = 5 sec
The person slips after every 5 m he climbs.
To Find,
The total time taken to reach the top of the building.
Solution,
Since it is given that
The person climbs 5 m and then slips 1 m
So,
To climb 1 m he took 5 sec
Time taken to climb 5 m = 5*5 = 25 sec
Now, he slips 1 m after climbing 5 m
In 25 seconds the person actually climbed 5-1 = 4m.
Total height of the building = 53m
So, 53/4= 13 (remainder 1 ignored as he will not slip after the last climb)
Time taken to climb the building = 25x13=325 sec
Hence, the time taken by the person to climb the building is 325 seconds.
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