a person was climbing on a building . he slips 1 m for every 5 metre he climbs up . if the building is 53 metre high and he takes 5 second to climb 1 metre , find the total time taken by him to get on the top of building. gyss please tell me the answer
Answers
Answer:
The expression for the time taken with two different modes of transport is t1X+t1Y=2(tX+tY)t1X+t1Y=2(tX+tY) where tX is the time taken when mode of transport X is used single way, tY is the time taken when mode of transport Y is used single way, t1Xt1X is the time taken when mode of transport X is used both ways and t1Yt1Y is the time taken when mode of transport Y is used both ways. Time is measure in seconds, minutes, and hours.
Answer and Explanation:
Given data
The height of a building is: h=53mh=53m .
The time taken by a person to climb 1 meter is: t=5sect=5sec.
The expression to calculate the time taken by a person to climb 5 meter is,
t′=t×5t′=5×5t′=25sect′=t×5t′=5×5t′=25sec
The person slips 1m for every 5m he climbs, so in actual he climb 4m in 25sec25sec.
The expression to calculate the time taken by a person to climb 1 meter is,
4m=25sec1m=25sec44m=25sec1m=25sec4
The expression to calculate the time taken to climb the building is,
T=h×254T=53×254T=331.25sT=h×254T=53×254T=331.25s
Thus, the total time taken by him to get on the top of the building is 331.25s331.25s.