a person weight 63 kg. the area under one foot of the person is 180 cm square. find the pressure exerted on the ground by the person ,when he was standing?
Answers
Answered by
11
Area = 180 cm² = 180 × 10^-4 m²
Pressure = Force / Area
= mg / A
= (63 kg × 9.8 m/s²) / (180 × 10^-4 m²)
= 34300 Pa
= 34.3 kPa
Pressure exerted by person on ground is 34.3 kPa
Pressure = Force / Area
= mg / A
= (63 kg × 9.8 m/s²) / (180 × 10^-4 m²)
= 34300 Pa
= 34.3 kPa
Pressure exerted by person on ground is 34.3 kPa
pranavjangan:
what is kpa
kilo pascals
Answered by
3
Answer: 17150 Pa or 1.715 Pa * 10^4
Explanation:
Total area (by both feet)= 2(180 cm^2)
=> 360cm^2
=> 360 * 10^-4 m^2
mass= 63kg
acceleration of gravity= 9.8 m/s
force = mass*acceleration
=> (63*9.8) N
=> 617.4 N
pressure= force/area
=> 63 * 9.8 N/ 360 * 10^-4 m^2
=> 1.715 * 10^4 Pascal
=> 17150 Pa
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