A person who invested ₹5600 at ₹ 14 . /. per annum compound interest for 3 years. calculate:amount at the end of first year. amount at the end of second year
Answers
Step-by-step explanation:
For the first year:
For the first year: P= Rs. 5,600, N=1 year and R=14%
For the first year: P= Rs. 5,600, N=1 year and R=14%We have S.I. =100PNR=1005,600×1×14= Rs. 784
For the first year: P= Rs. 5,600, N=1 year and R=14%We have S.I. =100PNR=1005,600×1×14= Rs. 784And Amount at the end of first year P+S.I.= Rs. 5,600+ Rs. 784= Rs. 6,384
For the first year: P= Rs. 5,600, N=1 year and R=14%We have S.I. =100PNR=1005,600×1×14= Rs. 784And Amount at the end of first year P+S.I.= Rs. 5,600+ Rs. 784= Rs. 6,384Now, for the second year :
For the first year: P= Rs. 5,600, N=1 year and R=14%We have S.I. =100PNR=1005,600×1×14= Rs. 784And Amount at the end of first year P+S.I.= Rs. 5,600+ Rs. 784= Rs. 6,384Now, for the second year :P= Rs. 6,384, N=1 year and R=14%
For the first year: P= Rs. 5,600, N=1 year and R=14%We have S.I. =100PNR=1005,600×1×14= Rs. 784And Amount at the end of first year P+S.I.= Rs. 5,600+ Rs. 784= Rs. 6,384Now, for the second year :P= Rs. 6,384, N=1 year and R=14%We have S.I.=100PNR=1006,384×1×14= Rs. 893.76
For the first year: P= Rs. 5,600, N=1 year and R=14%We have S.I. =100PNR=1005,600×1×14= Rs. 784And Amount at the end of first year P+S.I.= Rs. 5,600+ Rs. 784= Rs. 6,384Now, for the second year :P= Rs. 6,384, N=1 year and R=14%We have S.I.=100PNR=1006,384×1×14= Rs. 893.76To the nearest rupee, it is Rs. 894.
Step-by-step explanation:
8. The cost of 24 oranges is equal to the selling price of 18 oranges. Is there any gain or loss?
Find the gain or loss%.
the answer you have given is right but 33.34% how it is coming can you give me a photo. please tell as soon as possible.