A person with external body temperature 35°C is present in a room at temperature 25°C . Assuming the emissivity of the body of the person to be 0.5 and surface area of the body of the person as2.0m sqr, calculate the radiant power of the person
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chaubeypragati95:
What is this i want answer
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HEYAMATE,
HERE IS UR ANSWER.
The person radiates energy at a rate:
P = Q / ∆t =A[(T1)^4 - (T2)^4] , T1>T2
here, P is the radiant power of the person,
= 0.5 emissivity of the body of the person,
= 5.672 x10^-8 J/(s.m^2.K^4) is the Stefan – Boltzmann constant,
= 2.0m^2 is the surface area of the body of the person
and
T1 is the temperature of the person = 35+273 =308K
and T2 is the temperature of the surroundings = 25+273 =298K
Then, the radiant power of the person will be:
P = A[(T1)^4 - (T2)^4]
P = 0.5 x 5.672 x 10^-8 x 2 x[(308)^4 - (298)^4]
P = 5.672 x 10^-8 x 1113028080
P = 6313095269.76 x 10^-8
P = 63.13 W
I HOPE IT HELPS U.
HERE IS UR ANSWER.
The person radiates energy at a rate:
P = Q / ∆t =A[(T1)^4 - (T2)^4] , T1>T2
here, P is the radiant power of the person,
= 0.5 emissivity of the body of the person,
= 5.672 x10^-8 J/(s.m^2.K^4) is the Stefan – Boltzmann constant,
= 2.0m^2 is the surface area of the body of the person
and
T1 is the temperature of the person = 35+273 =308K
and T2 is the temperature of the surroundings = 25+273 =298K
Then, the radiant power of the person will be:
P = A[(T1)^4 - (T2)^4]
P = 0.5 x 5.672 x 10^-8 x 2 x[(308)^4 - (298)^4]
P = 5.672 x 10^-8 x 1113028080
P = 6313095269.76 x 10^-8
P = 63.13 W
I HOPE IT HELPS U.
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