A person X raises a load of 100kg to a height of 12 m in 5 minutes. Another person Y raises a load of 50 kg to a height of 15 m in 1.25 minutes.By what factor does the power of Y exceed that of X?Take g=10 m/s⁻².
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Answer: 60 W
Explanation:
Power for X ( P1 ) = work done / time
= mgh / t
= 100 * 10 * 12 / (5 * 60 )
= 40 W
Power of Y ( P2 ) = work done / time
= mgh / t
= 50 * 10 * 15 / ( 1.25 * 6 0)
= 100 W
Then. Power of Y exceeds X by = P 2 - P1
= 100 - 40
= 60 W
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