a personcoversonethirdoftotaldistanceat x m/s. and one fourthoftotaldistanceat 9m/s. findthe average speedofperson.
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Let us assume that the person travels 1m
A/c to the question
he covers 1/3m at xm/s
so time taken to cover 1/3m
=dist./speed={1/3}/x=1/3xsec
Similarly, he covers 1/4m at 9m/s
so time taken to travel 1/4m
=1/4/9=1/36sec
Average speed
=total distance traveled/time taken to travel that distance
={1/3+1/4} / {1/3x+1/36}
On simplifying you will get
avg. speed = 21x/(12+ x)
Hope it helps... :)
A/c to the question
he covers 1/3m at xm/s
so time taken to cover 1/3m
=dist./speed={1/3}/x=1/3xsec
Similarly, he covers 1/4m at 9m/s
so time taken to travel 1/4m
=1/4/9=1/36sec
Average speed
=total distance traveled/time taken to travel that distance
={1/3+1/4} / {1/3x+1/36}
On simplifying you will get
avg. speed = 21x/(12+ x)
Hope it helps... :)
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