A pespendicular AD on the base BC of triangle ABC
intersects Вс in D
such that BD = 3 CD
Prove that 2 A B² =2 AC²+ BC2?
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Step-by-step explanation:
The perpendicular from A on side BC of a ΔABC intersect BC at D such that DB=3CD. Prove that 2AB2=2AC2+BC2.
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