A petrol engine raises 200 kg of water in a well from a depth of 7 m in 6 s . show that the engine is developing about 2.33 kW of power.
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Mass(m)= 200kg
Height(h)= 7m
Time(t)= 6 seconds
Force of gravity (g)= 10m/(s*s)
Work done(W)= mgh
= 200X7X10
= 14000Joules
Since, power is equal to work done divided by time taken, so
Power= W/t
= 14000/6
= 2333.3333....W= 2333.3W
1 kW= 1000W
So, 2333.3W = 2333.3/1000= 2.33kW
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