Question

A petrol tank is a cylinder of base diameter 28cm and length 24cm fitted with conical ends each of axis length 9cm.Determine the capacity of the tank.

Answer 1

Volume of the cylindrical portion of the tank= TTr2h

=22/7 * (28/2)2 * 24cm3 

= 14784cm3

Volume of 2 conical ends

=2 (1/3 TTr2h) =2/3 TTr2h =2/3 * 22/7 *14*14 * 9cm3
=3696cm3

Therefore, capacity of the tank= 14784cm3 + 3696cm3= 18480cm3

Thus, capacity of the tank= 18480cm3

Answer 2

Given:

Base diameter of a cylinder(d) = 28 cm
Length of a cylinder (H)= 24 cm
Length of each conical part(h) = 9 cm
Radius of a cylinder = Radius of a cone(r ) = d/2 = 28/2 = 14 cm

Volume of the cylindrical part of the tank=πr²h
=(22/7) × (14)²×24
= (22/7) × 14× 14 ×24
=  22× 2 × 14 ×24
= 44 × 14 ×24
= 14784 cm³

Volume of 2 conical ends
=2(1/3 πr²h)
=2/3 πr²h
=2/3× (22/7) (14)²×9
= 2/3× (22/7) 14× 14 × 9
= 2 × 22 × 2 × 14 × 3
= 88 × 14 × 3
= 3696 cm³

CAPACITY of the tank= Volume of the cylindrical part of the tank + Volume of 2 conical ends
= 14784 cm³ + 3696 cm³
= 18480 cm³

Hence,the capacity of the tank= 18480 cm³

HOPE THIS WILL HELP YOU..