Question

A Pharmacist was required to make a solution chloride(NaCl).Calculate the concentration (in g/L) of sodium chloride that is prepared by dissolving 2.25 g of NaCl in 250 mL of distilled water

Answer 1

Answer: w/v% concentration = 0.9%.

Explanation:

We know,

w/v% concentration = (Weight of solute)/(Volume of solution) × 100%

=> w/v% = (2.25)/(250) × 100%

=> w/v% = 225/25000 × 100%

=> w/v% = 225/250% = 9/10% = 0.9%

More:

• w/w% concentration = (Mass of solute)/(Mass of solvent) × 100%
• v/v% concentration = (Volume of solute)/(Volume of solution) × 100%
• Molarity = (No. of moles of solute)/(Volume of solution)
• Molality = (No. of moles of solute)/(Mass of solvent)
• Mole fraction = (No. of moles of solute)/(No. of moles of solvent.)