Math, asked by alparajput01, 10 months ago

a photo measuring 7.5 CM by 7 cm is and large so that the larger side becomes 18cm what does the shorter side become in what ratio is the area increase​

Answers

Answered by abhash7
6

Answer:

a photo measures 7.5 cm

large = 7cm

become =18 cm

are

7.5 + 7.0 + 18.0

= 32 .5cm

Answered by kingofself
2

Answer:

The length of the shorter side is 12 cm and the ratio area increased by 5.76 : 1.

Solution:

Given Data:

A photo size 7.5 CM by 5 cm

To Find:

Calculate the area of the photo:

Step-by-step explanation:

Step 1:

The area of the photo is:

7.5 \times 5=37.5 \mathrm{cm}^{2}

Step 2:

Let x be the constant ratio

Ratio of Length: Width = 7.5x : 5x

Now the area of the largest side becomes 18cm.

7.5x = 18

Step 3:

\mathrm{x}=\frac{18}{7.5}

x = 2.4

Thus the width is 5x = 5 \times 2.4= 12 cm

Step 4:

Result:

The new length and width is 18 cm and 12 cm respectively.

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