Math, asked by Ratri2019, 1 year ago

Pls find answer it is urgent​

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Answered by shauryapaul01
1

Answer:

Step-by-step explanation: pqrs is a trapazium

let the angles be x

and angle p and angle s are in ratio 3:7

pq //rs ps is a transversal

3x+7x=180

10x=180

x=18

angle p =3x

               3*18

                54

angle s =7x

              7*18

               126

similarly 5x + 7x=180

             12x=180

            x=15

angle q=5x

            5*15

            75

angle r=7x

             7*15

             105

Answered by Shamz52003
1

Answer:

Step-by-step explanation:

angle p and angle s are co interior angle since PQ||RS

similarly angle R and angle Q are also co interior

P:S=3:7

LET THEIR COMMON RATIO BE X

SO,

P=3X

S=7X

P+S=180 (CO INTERIOR)

3X+7X=180

10X=180

X=18

P=3X=3*18=54 DEGREE

S=7*18=126DEGREE

SIMILARLY FOR ANGLE Q AND ANGLE R SINCE THEY ARE ALSO CO INTERIOR

Q:R=5:7

COMMON RATIO BE Y

Q=5Y

R=7Y

Q+R=180

5Y+7Y=180

12Y=180

Y=15

Q=5*15=75 DEGREE

R=7*15=105 DEGREE

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