A photon creates a pair of electron - positron with equal kinetic energy. Let kinetic energy of each particle is 0.29 Mev then what should be the energy of the photon
Answers
Answered by
24
The minimum energy of photon to undergo
pair production is 0.51MeV for each particle
and total willbe 1.02MeV
As electron and positron are produced it
means that photon has energy of 1.02MeV but
each has K.E of 0.29MeV it means that surplus
energy is converted to K.E
hence total energy of photon is
= 1.02+0.58(for two particles)
=1.6MeV
pair production is 0.51MeV for each particle
and total willbe 1.02MeV
As electron and positron are produced it
means that photon has energy of 1.02MeV but
each has K.E of 0.29MeV it means that surplus
energy is converted to K.E
hence total energy of photon is
= 1.02+0.58(for two particles)
=1.6MeV
Similar questions