Question

A photon has a frequency of 7.3 × 10–17 Hz. Planck’s constant is 6.63 × 10–34 J•s.

The energy of the photon, to the nearest tenths place, is × 10–50 J.

Answer 1

Answer:

E = hv

Where,

E = Energy of Photon

h = Plank's Constant

v = Frequency of Photon

By applying the above formula,

→ $E = 7.3 \times {10}^{ - 17} \times 6.63 \times {10}^{ - 34} J$

→ $E = 48.3 \times {10}^{ - 50} J$

So, K = 48.3