A photon of 100 Å is absorbed by a body and it emitted the total energy in form of two photons of equal energy. The frequency of emitted photon is
1.5 × 1016 Hz
3 × 1015 Hz
6.4 × 1018 Hz
3.5 × 1012 Hz
Answers
Answer:
Explanation:
Well here I am not going tell you a calculations just I am telling you concepts and steps how to tackle above problem
We had given photon of 100A° wavelength so from wavelength you can calculate energy of photon as follows
E=hc/wavelength ........(1)
Let this is the total energy given by this photon to a body
Then , body released two photons having equal energy
Now ,
Accor6to pricpke of conservation of energy,
Total energy given by photon of 100A° wavelength = sum of energies of photons emitted
= 2×energy of one photon emitted.........(as both has equal energies)
From above equation you will get energy of that released one photon
Now a little simple step
Put that energy of released photon in formula
E=h×frequency of released photon
And then calculate the frequency of that photon and this the answer that you wanted
Remember to keep units same if you were to take your Planck's constant in joule take it in joule for whole of the problem
Here H=6.626×10^-34 joules