Question

A photon of energy 12.75 ev is completely absorbed by a hydrogen atom initially in groundstate the principal quantum number of the excited state is

Answer 1

E = energy absorbed = 12.75 eV

n₂ =principle quantum number value in excited state = ?

energy absorbed in case of hydrogen is given as

Energy in excited stated = energy in ground state + energy absorbed

Energy in excited stated = - 13.6 + 12.75

Energy in excited stated = - 0.85 eV

- 13.6/n²₂ = - 0.85

n₂ = 4

Answer 2

Answer:

correct.

Explanation:

correct , thanks.