A photon of energy 12.75 ev is completely absorbed by a hydrogen atom initially in groundstate the principal quantum number of the excited state is
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E = energy absorbed = 12.75 eV
n₂ =principle quantum number value in excited state = ?
energy absorbed in case of hydrogen is given as
Energy in excited stated = energy in ground state + energy absorbed
Energy in excited stated = - 13.6 + 12.75
Energy in excited stated = - 0.85 eV
- 13.6/n²₂ = - 0.85
n₂ = 4
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correct.
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correct , thanks.
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