Chemistry, asked by ajgamboa2, 8 months ago

A photon of light has a wavelength of 2.55e(-12) meters. Calculate the corresponding frequency.

Answers

Answered by Anonymous

3

Hi There !

Here is your Answer !

Answer:

The energy of the photons emitted in transition n=4→n=2 is

hv=13.6eV[122−142]=2.55eV

The maximum kinetic energy of the photonelectrons is

=2.55eV−1.9eV=0.65eV

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