Physics, asked by sinchanag84, 2 months ago

A physical quantity Pis described by the relation
P = a^1/2 b^2 c^3 d^4
If the relative errors in the measurement of a, b, c and d, respectively, are 2%, 1%,
3% and 5%, then the relative error in P will be
(A) 8%
(B) 32%
(C) 12%
(D) 25%​

Answers

Answered by RohithArockiaInfant
1

Answer:

32℅

Explanation:

Relative error =1/2 ×Δa/a +2×Δb/b+3×Δc/c +4 ×Δd/d

                       =1/2 x 2℅ + 2 x 1℅ + 3× 3℅ +4 × 5℅

                        = 1/100 + 2/100+9/100+20/100  

                       = 32℅

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