Question

a physical quantity prelatedbto observales a, b, c p= a^3 b^2
$\sqrt{ \sqrt{cd} }$
cd​

Answer 1

Answer:

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Answer 2

Answer:

The percentage error in P is 13%.

Explanation:

Given that,

P=a^3b^2(\sqrt{c}d)

a = 1%

b= 3%

c=4%

d=2%

The percentage error in P

\dfrac{\Delta P}{P}\times100=[3\times\dfrac{\Delta a}{a}+2\times\dfrac{\Delta b}{b}+\dfrac{1}{2}\dfrac{\Delta C}{C}+\dfrac{\Delta d}{d}]\times100

\dfrac{\Delta P}{P}\times100=[3\times\dfrac{1}{100}+2\times\dfrac{3}{100}+\dfrac{1}{2}\times\dfrac{4}{100}+\dfrac{2}{100}]\toimes100

\dfrac{\Delta P}{P}\times100=[\dfrac{3+6+2+2}{100}]\times100

\dfrac{\Delta P}{P}\times100=[\dfrac{13}{100}]\times100

\dfrac{\Delta P}{P}\times100=13\%