Math, asked by llXxDramaticKingxXll, 7 days ago

A physical quantity X is depending upon physical quantities A and B by the relation X = a^{2} - ({a}^{3} \div b) In an experiment the value of A is measured as (2.0±0.2) and of B is measured as (1.0±0.1). Then represent the value of X.​

Answers

Answered by sabyasachibanik517
2

Answer:

Answer

X

ΔX

×100=±[2

a

Δa

+3

b

Δb

+

2

5

c

Δc

+2

d

Δd

]×100

X

ΔX

×100=±[

100

2×1

+

100

3×2

+

2

5

×

100

3

+

100

2×4

]100

100

100

[2+6+

2

15

+8]

X

ΔX

×100=±[16+

2

15

]=±[

2

32+15

]=±

2

47

=±23.5%

Mean absolute error =±

100

23.5

=±0.235

=0.24 (rounding off in significant figure)

Again rounding off X=2.763 in two significant figure =2.8

Answered by SaniyaGurav897
8

Answer:

The right answer is 0. 24

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