Question

a picture 32 cm long and 12 cm wide is to be enlarged so that it's length will become 56 cm. what will be the width of the enlarged picture.

Answer 1

Ratio of Length : Width = 32 : 12 (Given)

Simplify by dividing by 4:

Ratio of Length : Width = 8 : 3

Define x:

Let x be the constant ratio

Ratio of Length : Width = 8x : 3x

Solve x:

8x = 56

x = 7

Find the width:

width = 3x = 3(7) = 21 cm

Answer: The width is 21 cm

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ALTERNATIVE METHOD:

$\dfrac{\text{Length 1}} {\text{Width 1}}= \dfrac{\text{Length 2}} {\text{Width 2}}$

$\dfrac{\text{32}}{\text{12}}= \dfrac{\text{56} }{\text{Width2}}$

$32 \times \text{Width}= 12 \times 56$

$32 \times \text{Width}= 672$

$\text{Width}= 21$

Answer 2

This is your answer
Let Width of enlarge picture is x
so 32: 12 = 56 : x
x = 56 x 12/32
x =21
Hope it helps