Question

a picture has 15cm by 2.5cm dimensions .a 2.5 cm broad frame is required to cover it .find the cost of the frame at ₹1.50 per sq.cm.​

Answer 1

Answer:

Total cost of frame is $168.75

Since we have given that

Length of a picture = 15 cm

Width of a picture = 2.5 cm

so, Area of a picture is given by

\begin{gathered}A=Length\times Width\\\\A=15\times 2.5\\\\A=37.5\ cm^2\end{gathered}

A=Length×Width

A=15×2.5

A=37.5 cm

2

As we have that frame 2.5 cm broad is required to cover it.

So, Length of outer part becomes

\begin{gathered}15+2.5+2.5\\\\=20\ cm\end{gathered}

15+2.5+2.5

=20 cm

Width of outer part becomes

\begin{gathered}2.5+2.5+2.5\\\\=7.5\ cm\end{gathered}

2.5+2.5+2.5

=7.5 cm

so, Area of outer part is given by

\begin{gathered}20\times 7.5\\\\=150\ cm^2\end{gathered}

20×7.5

=150 cm

2

So, Area of frame =Area of outer part - Area of picture

\begin{gathered}150-37.5\\\\=112.5\ cm^2\end{gathered}

150−37.5

=112.5 cm

2

Cost of the frame =$1.50 per sq. cm.

So, Total cost becomes

\begin{gathered}112.5\times 1.50\\\\=\$168.75\end{gathered}

112.5×1.50

=$168.75

Hence, Total cost of frame is $168.75.

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Answer 2

Given :-

• Length of the picture = 15 cm
• Breadth of the picture = 2.5 cm
• Width of the picture = 2.5 cm
• Rate of framing = Rs. 1.50 per sq. cm

To Find :-

• The cost of framing the picture at Rs. 1.50 per sq. cm.

Solution :-

Using the formula,

Area of a rectangle = l × b

Where,

• A = Area
• L = Length
• B = Breadth

Substituting their values,

= 15 × 2.5

= 37.5 sq. cm

Dimensions of the outer part,

• Length = 15 + 2.5 + 2.5 = 20 cm
• Breadth = 2.5 + 2.5 + 2.5 = 7.5 cm

Area of the outer part,

Area = Length × Breadth

= 20 × 7.5

= 150 sq. cm

Area of the frame = 150 - 37.5

= 112.5 sq. cm

Finding the rate,

Total cost = 112.5 × 1.50 = Rs. 168.75

Therefore, the cost of the frame is Rs. 168.75.