Math, asked by BrainlyHelper, 1 year ago

A Piece of cloth costs ₹ 200. If the piece was 5m longer and each metre of cloth costs ₹ 2 less, the cost of the piece would have remained unchanged. How long is the piece and what is the original rate per metre?

Answers

Answered by nikitasingh79
45
Let the length of the piece be x m.
Rate per metre = ₹ 200/x

New length = x +5 m
New rate per metre = ₹ 200/x+5

ATQ
200/x - 200/x+5 = 2
200(x+5) - 200x / x(x+5) = 2
200x + 1000 -200x / x² +5x = 2
1000 / x² +5x = 2
2(x² +5x ) = 1000
x² + 5x = 1000/2
x² + 5x = 500
x² +5x -500= 0
x² +25x -20x -500= 0
x(x+25) -20(x +25)= 0
(x-20) ( x+25)= 0

(x-20) = 0 or  ( x+25)= 0

x = 20  or  x = -25 (Length can't be negative)
So,x = 20.

Rate per metre = ₹ 200/x = ₹ 200/20= ₹ 10.

Hence, the length of the piece of cloth is 20 m and the rate = ₹ 10 per m.

HOPE THIS WILL HELP YOU..
Answered by AlwysGonaHelpSome12
10

Hey There! ☺

Nice Questions! ♥

Let's unlock the answers now…

==============================================

Important so read it:-

+++++++++++++++

Let the piece of cloth is x metre and it costs Rs.y/metre. Then by the given conditions 

∴, xy=200 -------------(1) and

+++++++++++++++++++++

(x+5)(y-2)=200

++++++++++++++++

or, xy+5y-2x-10=200

+++++++++++++++

or, 200+5y-2x-10=200

++++++++++++++++++

or, 5y-2x-10=0

++++++++++++

or, 5y=2x+10

or, y=(2x+10)/5

Putting in (1),

x(2x+10)/5=200

or, x(2x+10)=200×5

or, 2x²+10x=1000

or, x²+5x-500=0

or, x²+25x-20x-500=0

or, x(x+25)-20(x+25)=0

or, (x+25)(x-20)=0

either, x+25=0

or, x=-25

or, x-20=0

or, x=20

Since the length of the cloth can not be negative,

∴, x=20 metre


+++++++++++++

Putting in (1),

20y=200

or, y=10

∴, the cloth is 20 m long and the original rate is Rs. 10/metre:)


++++++++++++++++++++++++++++++++++++++++++++++++


==============================================

Hope my answer helped … ☺
Similar questions