Question

A piece of copper of mass 106g is dipped in a measuring cylinder containing water at 22ml mark.The water rises to 34ml mark.Find the volume and density

Answer 1

It is given that the volume of water before the copper piece was placed is 22 ml, and after the copper piece was placed in the container, the total volume (copper+water) became 34 ml.

Therefore, we can deduce that the volume of copper is the difference between those two volumes.

$v_{copper}=34-22=12\:ml$

Density is the mass per unit volume.

Therefore, $density=\frac{mass}{volume}\\=\frac{106}{12}\\=8.83\:gm/ml\\=8.83\:gm/cm^3$

Answer 2

Answer:

Explanation:

It is given that the volume of water before the copper piece was placed is 22 ml, and after the copper piece was placed in the container, the total volume (copper+water) became 34 ml.

Therefore, we can deduce that the volume of copper is the difference between those two volumes.

Density is the mass per unit volume.

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