The total number of electron present in 1ml Mg. Given density of Mg=1.2g/ml
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Mass of magnesuium present = 1ml x 1.2 gm/ml =1.2 grams.
Molar mass of Mg = 24.
Hence moles of Mg present = 1.224=0.05 moles
No. of electrons = 0.05×6.023×1023 = 3.0115×1022
Molar mass of Mg = 24.
Hence moles of Mg present = 1.224=0.05 moles
No. of electrons = 0.05×6.023×1023 = 3.0115×1022
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