Question

A piece of copper of mass 120 g is heated in an enclosure to a temp of 125.It is then taken out of the enclosure and held in for half a minute

Answer 1

Answer:

Hey mate here is your answer......

Firstly m1•c1•(100-24.1)= m2•c2•(24.1-16) + m3•v3•(24.1-16),

c1 = (m2•c2+ m3•v3)•8.1/m1•75.9 =

= 811 J/kg•degr =0.194 cal/g•degr

Hope it's helpful for you...

Explanation: