a piece of equipment cost a certain factory rs 600000 if it depreciates in values 15% the first 13.5% the next year 12% the third year and so on what will be its value at the end of 10 years all percentage applying to the original cost
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present cost = 600000
600000×15/100 +600000×12.5/100+ .......
cost decreasing per year is in AP series
1st term(a) = 15 no. of term=10 ,
Common difference(d) = -1.5 (negative)
cost after 10 years==
=600000/100×(15 +13.5+12+ 10.5 .......10th term)
=600000/100 ×( Sn=n/2{2a+(n-1)d}
=6000×{5×(30+ 9×-1.5)}
=6000×5×16.5
=30000×16.5
= 495000 Rs.
600000×15/100 +600000×12.5/100+ .......
cost decreasing per year is in AP series
1st term(a) = 15 no. of term=10 ,
Common difference(d) = -1.5 (negative)
cost after 10 years==
=600000/100×(15 +13.5+12+ 10.5 .......10th term)
=600000/100 ×( Sn=n/2{2a+(n-1)d}
=6000×{5×(30+ 9×-1.5)}
=6000×5×16.5
=30000×16.5
= 495000 Rs.
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