a piece of iron has volume 40 cm³ and has a mass of 300 g find the density of iron in CGS system
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Answered by
0
Answer:
Answer
Correct option is
C
6.8 N
Given that,
Volume of body V=10−4m3
Density of iron, ρi=7800kgm−3
Density of water ρw=1000kgm−3
Weight in air,Wa=ρiVg=7800×10−4×10=7.8N
We know that,
Weight in water = weight in air – buoyancy force
Ww=Wa−ρwVg
Ww=7.8−1000×10−4×10
Ww=6.8N
Hence, the weight of body in water is 6.8 N
Answered by
0
Answer:
Given that,
Volume of body V=10
−4
m
3
Density of iron, ρ
i
=7800kgm
−3
Density of water ρ
w
=1000kgm
−3
Weight in air,W
a
=ρ
i
Vg=7800×10
−4
×10=7.8N
We know that,
Weight in water = weight in air – buoyancy force
W
w
=W
a
−ρ
w
Vg
W
w
=7.8−1000×10
−4
×10
W
w
=6.8N
Hence, the weight of body in water is 6.8 N
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