Question

Is 101 a term of the arithmetic sequence of 13,24,35........
How about 1001?
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Answer 1

Answer:

same for 1001

Step-by-step explanation:

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Answer 2

Answer:

a=13   d=11

101=13+(n-1)11

101=13+11n-11

101=2+11n

99=11n

n=9

since n can be 9, therefore 101 is one of the terms of the given AP

1001=13+(n-1)11

1001=13+11n-11

1001=2+11n

11n=999

n=999/11=90.81...

n can'tbe a fraction

therefore, 1001 is not a term of the given AP

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