A piece of iron weighs 44.5 gf in air. If the density of iron is 8.9 × 10^3 kg m^-3 , find the weight of iron peice which immersed in water.
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Given:
Weight of iron piece = 44.5 gf
The density of iron = 8.9 x 10³ m³
To Find:
Weight of iron piece immersed in water.
Solution:
Density of iron = 8.9 x 10³
= 8900
Density of the water = 10³
= 1000
Weight of iron in water = Weight of iron in air x ( 1 - water density/iron density)
= 44.5 gf x ( 1 - 1000/8900)
= 39.5
Answer: The Weight of iron piece immersed in water is 39.5 kgf
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