Question

A piece of material weighing 50 g is coated with 6.3 g of wax of relative density 0.9. If the coated piece weighs 16.3 g in water, the density of the material is

Answer 1

Given in the question :-

Mass of Material = 50 g.

Mass of wax = 6.3 g.

Therefore,  mass of material + mass of wax = 56.3 g

Now,

Loss in weight in water = 56.3 g - 6.3 g

Loss in weight in water = 40 g.

Volume of water displaced = 40 cm.

By the formula,

∴ Volume of water displaced = Material weighing / density  + wax weighing  / density

$\frac{50}{\rho} + \frac{6.3}{9} = 40$

$\frac{50}{\rho} = 33$

$\rho = \frac{50}{33}$

ρ = 1.515

Hence the density of the material is 1.515

Hope it helps

Answer 2

Hey Mate ⭐⭐⭐

Here's ur answer ⤵

=>50+ 6.3 = 56.3 g

=>56.3 g - 16.3 g=40. G

Volume of water displaced is 40 cm.

50/p + 6.3/9=40

50/p=33

p= 50/33

=> p= 1.515

If the coated piece weighs 16.3 g in water, the density of the material is ρ = 1.515

Hope it helps you! ヅ

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