Question

A piece of metal of mass 112g is heated to 100°C and dropped into
mass 40g containing 200g of water at 16°C. Neglecting heat loss, the specie
is nearly, if the equilibrium temperature reached is 24.1°C,
glecting heat loss, the specific heat of the metal
A) 0.294 cal/gm°C B) 0.394 cal/gm°C C) 0.194 cal/gm°C D) 0.494 cal/gm°C​

Answer 1

Answer:

c. 0.194 cal/gm°C

Explanation:

m1•c1•(100-24.1) = m2•c2•(24.1-16) + m3•v3•(24.1-16),

c1 = (m2•c2+ m3•v3)•8.1/m1•75.9 =  = 811 J/kg•degr =0.194 cal/g•degr

Answer 2

Answer:

I think it is 0.194 cal/g degree C (C)