Question

a piece of metal weighs 50 Newton's in a 36 Newtons in water and 41 Newtons in oil density of oil​

Answer 1

Answer:

Density of oil is 642.909 kg/m³.

Explanation:

The give data :-

Weight of metal in air or true wight of metal ( T ) = 5 N

Weight of metal in watar ( W ) = 36 N

Weight of metal in oil ( W' ) = 41 N

W = buoyancy force of water + true weight

36 = ρ * g * v + 50         ( v = volume of metal )

36 = 1000 * 9.81 * v + 50

-14 = 1000 * 9.81 * v

v = 0.001427 m³

W' = Buoyancy force of oil + true weight.

41 =   ρ * g * v + 50

-9 =  ρ * 9.81 *  0.001427

ρ = 642.909 kg/m³.

Answer 2

Given

Metal Weight =50 Newton

Metal Weight in water=36 Newtons

Metal weight in oil=41 Newtons

To find

Oil density =??

Solution

We have determined the weight by the given formula that are mention below

$W = buoyancy\ force\ of\ water + true\ weight$

putting the value into the formula we get

$36 = \ p\ * g\ * v\ + \ 50$

$36 = 1000 * 9.81 * v + 50-14 = 1000 * 9.81 * vv = 0.001427 m³$

Again uses the above formula

$41 =\ p\ *\ g \ * v + 50$

$p = 642.909 kg/m³.$