Question

A piece of metal with a mass of 15.3 grams has a temperature of 50.0 ºC. When the metal is placed in 80.2 grams of water at 21.0ºC, the temperature rises by 4.3 ºC. What is the specific heat capacity of the metal?

Answer 1

Specific heat capacity of metal =  3.820 KJ/kgK

Given:

Mass of metal, m₁ = 15.3 gm

Temperature of Metal, T₁ = 50°C

Mass of water, m₂ = 80.2 gm

Temperature of water, T₂ = 21°C

Change in temperature of water, ΔT = 4.3°C

Final temperature of metal = 25.3°C

To Find:

Specific heat capacity of metal

Explanation:

Let the specific heat capacity of metal be c₁ and specific heat capacity of    water c₂ be 4.186 KJ/kgK

Change in temp of metal ΔT' = 50 - 25.3 = 24.7°C

Since we know that,

Heat lost by the piece of metal = Heat gained by the water

m₁ × c₁ × ΔT' = m₂ × c₂ × ΔT

15.3 × c₁ × 24.7 = 80.2 × 4.186 × 10³ × 4.3

c₁ =  $\frac{1443.584 \times \ 10^3}{377.91}$

c₁ =  3.82 KJ/kgK

Specific heat capacity of metal =  3.82  KJ/kgK

To learn more...

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