A piece of resistance wire has resistance of 16 ohm.Its diameter is doubled. Now its resistance will be ?
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Explanation:
R 1 = 16 ohm
diameter d1 = d
diameter d2 = 2d
R is inversely proportional to (diameter)^2
R1/R2 = d^2/4d^2
16/R2 = 1/4
R2 = 64
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