Question

A piece of sealing wax weights 0.27 kgf i air and 0.12 kgf when immersed in water calculate relatively density and appearent weight in a liquid of density 800

Answer 1

The apparent weight = 0.23 kgf

Explanation:

When a solid substance is placed in liquid , its weight decreases . By this phenomenon , the relative density of substance can be found by the relation

d = $\frac{W_1}{W_1-W_2}$

here W₁ = weight of wax in air

and W₂ = weight of wax in water

Therefore density d = 0.27/( 0.27 - 0.12) = 0.27/0.15 = 9/5 = 1.8

Now the density of liquid is 800 ( given )

The relative density = 800/1000 = 0.8

Therefore 0.8 = 0.27/( 0.27 - W₂)

0.27 - W₂ = 0.27/0.8 = 0.034

Thus W₂ = 0.27 - 0.034 = 0.23 kgf

Answer 2

Answer:

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