A piece of silver has a resistance of 6ohms what will be the resistance of a maganium wire of 1/3rd the length and 1/3rd the diameter if the p of magnium is 30 times of silver
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Answer:
90 ohms
Explanation:
1/3 L = 1/3 R
1/3 D = 1/9 A
So,
R = 1/3*9*30*1
= 90 Ohm.
Resistance = 90 Ohm.
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